1. **State the problem:** We need to find the average acceleration of the Koenigsegg Agera R as it goes from 0.00 mph to 60.0 mph in 2.90 seconds. 2. **Formula for average acceleration:** $$a = \frac{\Delta v}{\Delta t}$$ where $a$ is acceleration, $\Delta v$ is the change in velocity, and $\Delta t$ is the change in time. 3. **Convert velocity from mph to m/s:** Since 1 mph = 0.44704 m/s, $$60.0\ \text{mph} = 60.0 \times 0.44704 = 26.8224\ \text{m/s}$$ 4. **Calculate change in velocity:** $$\Delta v = 26.8224 - 0 = 26.8224\ \text{m/s}$$ 5. **Calculate average acceleration:** $$a = \frac{26.8224}{2.90}$$ 6. **Show intermediate step with cancellation:** $$a = \frac{\cancel{26.8224}}{\cancel{2.90}} \times \frac{26.8224}{2.90}$$ 7. **Simplify:** $$a \approx 9.25\ \text{m/s}^2$$ **Final answer:** The average acceleration is approximately $9.25$ m/s².