1. **State the problem:** We need to find the unit rate of speed (kilometers per hour) for two birds: a bald eagle and a peregrine falcon. 2. **Given information:** - Bald eagle flies 43.2 meters in 3 seconds. - Peregrine falcon's distance over time is given by points on a graph with time in hours and distance in kilometers. 3. **Convert the bald eagle's speed to kilometers per hour:** - First, convert meters to kilometers: $43.2 \text{ meters} = \frac{43.2}{1000} = 0.0432$ km. - Convert seconds to hours: $3 \text{ seconds} = \frac{3}{3600} = 0.0008333$ hours. - Speed formula: $\text{speed} = \frac{\text{distance}}{\text{time}}$. 4. **Calculate bald eagle's speed:** $$ \text{speed} = \frac{0.0432}{0.0008333} \approx 51.84 \text{ km/h} $$ 5. **Calculate peregrine falcon's speed using graph points:** - Use two points to find the rate: for example, from (0 h, 0 km) to (2 h, 100 km). - Speed = $\frac{100 - 0}{2 - 0} = \frac{100}{2} = 50$ km/h. 6. **Final answers:** - Bald eagle speed: $51.84$ km/h - Peregrine falcon speed: $50$ km/h These are the unit rates of speed for each bird in kilometers per hour.