1. **Problem statement:** Calculate the total charge stored in a circuit with three capacitors connected in parallel, given the voltage and capacitances. 2. **Formula used:** For capacitors in parallel, the total capacitance is the sum of individual capacitances: $$C_T = C_1 + C_2 + C_3$$ The charge stored is given by: $$Q = C_T \times V$$ 3. **Given values:** - $C_1 = 68\ \mu F$ - $C_2 = 12\ \mu F$ - $C_3 = 47\ \mu F$ - $V = 110$ 4. **Calculate total capacitance:** $$C_T = 68 + 12 + 47 = 127\ \mu F$$ 5. **Calculate total charge:** $$Q = 127 \times 110 = 13970\ \mu C$$ 6. **Explanation:** Since the capacitors are in parallel, their capacitances add directly. Multiplying the total capacitance by the voltage gives the total charge stored. **Final answer:** $$Q = 13970\ \mu C$$