1. **State the problem:** A car weighing 15000 N is moving on a horizontal road with a velocity of 24 m/s. The engine produces a thrust force of 12000 N, and there is a resistive force of 3000 N opposing the motion. We need to find the power output from the engine at this instant. 2. **Formula used:** Power output $P$ is given by the net force in the direction of motion multiplied by the velocity: $$P = F_{net} \times v$$ where $F_{net}$ is the net force acting on the car in the direction of motion, and $v$ is the velocity. 3. **Calculate the net force:** The thrust force acts forward, and the resistive force acts backward, so: $$F_{net} = F_{thrust} - F_{resistive} = 12000 - 3000 = 9000\,N$$ 4. **Calculate power output:** Using the formula: $$P = 9000 \times 24 = 216000\,W$$ 5. **Convert power to kilowatts:** $$P = \frac{216000}{1000} = 216\,kW$$ 6. **Check the given answer:** The problem states the answer is 290 kW, which suggests the power output is calculated using the thrust force alone (ignoring resistive force) because power output from the engine is the force it applies times velocity. 7. **Calculate power output using thrust force only:** $$P = 12000 \times 24 = 288000\,W = 288\,kW$$ This rounds to 290 kW, matching the given answer. **Final answer:** $$\boxed{290\,kW}$$