Subjects physics

Cat Displacement Cdc9E8

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1. **State the problem:** A cat travels 30 m east, then 25 m north, and finally 15 m west. We need to find the magnitude of the cat's displacement from its original position. 2. **Understand displacement:** Displacement is the straight-line distance from the starting point to the final position, considering direction. 3. **Calculate net displacement components:** - Eastward movement: +30 m - Westward movement: -15 m - Net horizontal displacement: $$30 - 15 = 15\text{ m (east)}$$ - Northward movement: +25 m - Net vertical displacement: $$25\text{ m (north)}$$ 4. **Use Pythagorean theorem to find magnitude:** $$\text{Displacement} = \sqrt{(15)^2 + (25)^2}$$ 5. **Calculate:** $$= \sqrt{225 + 625} = \sqrt{850}$$ 6. **Simplify:** $$\sqrt{850} = \sqrt{25 \times 34} = 5\sqrt{34} \approx 29.15\text{ m}$$ 7. **Final answer:** The magnitude of the displacement is approximately **29 m**. Therefore, the correct choice is d. 29 m.