1. **State the problem:** A cat travels 30 m east, then 25 m north, and finally 15 m west. We need to find the magnitude of the cat's displacement from its original position.
2. **Understand displacement:** Displacement is the straight-line distance from the starting point to the final position, considering direction.
3. **Calculate net displacement components:**
- Eastward movement: +30 m
- Westward movement: -15 m
- Net horizontal displacement: $$30 - 15 = 15\text{ m (east)}$$
- Northward movement: +25 m
- Net vertical displacement: $$25\text{ m (north)}$$
4. **Use Pythagorean theorem to find magnitude:**
$$\text{Displacement} = \sqrt{(15)^2 + (25)^2}$$
5. **Calculate:**
$$= \sqrt{225 + 625} = \sqrt{850}$$
6. **Simplify:**
$$\sqrt{850} = \sqrt{25 \times 34} = 5\sqrt{34} \approx 29.15\text{ m}$$
7. **Final answer:** The magnitude of the displacement is approximately **29 m**.
Therefore, the correct choice is d. 29 m.
Cat Displacement Cdc9E8
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.