1. **Problem Statement:** A car accelerates from rest at a constant rate of $3\ \text{m/s}^2$ for $5$ seconds. Calculate the final velocity and the distance traveled during this time.
2. **Formulae and Rules:**
- Final velocity: $v = u + at$
- Distance traveled: $s = ut + \frac{1}{2}at^2$
- Initial velocity $u = 0$ since the car starts from rest.
3. **Calculations:**
- Final velocity: $v = 0 + 3 \times 5 = 15\ \text{m/s}$
- Distance traveled: $s = 0 \times 5 + \frac{1}{2} \times 3 \times 5^2 = \frac{1}{2} \times 3 \times 25 = 37.5\ \text{m}$
4. **Explanation:**
The car starts from rest, so initial velocity is zero. Using the constant acceleration formulas, we find the final velocity after $5$ seconds and the total distance covered in that time.
**Final answers:**
- Final velocity: $15\ \text{m/s}$
- Distance traveled: $37.5\ \text{m}$
Constant Acceleration 630C17
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