1. **State the problem:** We have the volume $V$ as a function of time $t$ given by
$$V = X + \frac{Y}{t} + Z t^4$$
We need to find the correct dimensional formulas for $X$, $Y$, and $Z$ assuming the equation is dimensionally correct.
2. **Recall the dimension of volume:** Volume has dimension of length cubed, i.e.,
$$[V] = L^3$$
3. **Analyze each term:** Since the sum of terms must have the same dimension, each term must have dimension $L^3$.
- For $X$, since it is added directly to $V$, its dimension must be
$$[X] = L^3$$
- For $\frac{Y}{t}$, the dimension is
$$\left[\frac{Y}{t}\right] = \frac{[Y]}{[t]} = L^3$$
Therefore,
$$[Y] = L^3 \times [t] = L^3 T$$
- For $Z t^4$, the dimension is
$$[Z t^4] = [Z] \times [t]^4 = L^3$$
Therefore,
$$[Z] = \frac{L^3}{T^4} = L^3 T^{-4}$$
4. **Match with options:**
- $X = L^3$
- $Y = L^3 T$
- $Z = L^3 T^{-4}$
This corresponds to option **b**.
**Final answer:** Option b: $X = L^3$, $Y = L^3 T$, $Z = L^3 T^{-4}$
Dimensional Analysis A825Af
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