1. **Problem statement:** Mika's sweater rubs against her cotton shirt, charging her body. A piece of lint with charge $1.60 \times 10^{-19}$ C experiences a force of $3.2 \times 10^{-9}$ N near Mika. We need to find the electric field at that location. 2. **Formula used:** The electric field $E$ is related to force $F$ and charge $q$ by the formula: $$E = \frac{F}{q}$$ where - $E$ is the electric field (in N/C), - $F$ is the force experienced by the charge (in N), - $q$ is the charge (in C). 3. **Important rules:** - The electric field direction is the direction of the force on a positive charge. - The magnitude of the electric field is the force per unit charge. 4. **Substitute the given values:** $$E = \frac{3.2 \times 10^{-9}}{1.60 \times 10^{-19}}$$ 5. **Simplify the fraction:** $$E = \frac{\cancel{3.2} \times 10^{-9}}{\cancel{1.60} \times 10^{-19}} \times \frac{2}{2} = \frac{2 \times 10^{-9}}{1 \times 10^{-19}}$$ 6. **Calculate the power of ten:** $$E = 2 \times 10^{-9 - (-19)} = 2 \times 10^{10}$$ 7. **Final answer:** The electric field at the location is $$E = 2 \times 10^{10} \text{ N/C}$$ The direction is the same as the force on the positive charge (lint).