1. **Problem 1:** Mika's sweater charges her body, and a lint piece with charge $1.60 \times 10^{-19}$ C experiences a force of $3.2 \times 10^{-9}$ N. Find the electric field at that location. 2. **Formula:** The electric field $E$ is related to force $F$ and charge $q$ by $$E = \frac{F}{q}$$ This means the electric field is the force per unit charge. 3. **Calculation for Problem 1:** $$E = \frac{3.2 \times 10^{-9}}{1.60 \times 10^{-19}}$$ 4. Simplify the fraction: $$E = \frac{3.2}{1.60} \times \frac{10^{-9}}{10^{-19}} = 2 \times 10^{10} \text{ N/C}$$ 5. **Problem 2:** A force of 5 N acts on a charge of $6 \mu C = 6 \times 10^{-6}$ C. Find the electric field intensity. 6. Use the same formula: $$E = \frac{F}{q} = \frac{5}{6 \times 10^{-6}}$$ 7. Simplify: $$E = \frac{5}{6} \times 10^{6} = 0.8333 \times 10^{6} = 8.33 \times 10^{5} \text{ N/C}$$ 8. **Problem 3:** A charge of $4 \mu C = 4 \times 10^{-6}$ C exerts a force of $3.6 \times 10^{-4}$ N to the right on a positive test charge. Find magnitude and direction of electric field. 9. Calculate magnitude: $$E = \frac{3.6 \times 10^{-4}}{4 \times 10^{-6}} = 90 \text{ N/C}$$ 10. Direction: Since force is to the right on a positive charge, electric field is also to the right. **Final answers:** 1. $E = 2 \times 10^{10}$ N/C 2. $E = 8.33 \times 10^{5}$ N/C 3. $E = 90$ N/C to the right