1. **Problem:** Determine the components of the 1500-lb force $F$ along the oblique axes $a$ and $b$. Given: - Force magnitude $F = 1500$ lb - Angle between $F$ and axis $a$ is $70^\circ$ - Angle between axis $b$ and baseline is $35^\circ$ 2. **Formula:** To find the component of a force along an axis, use the projection formula: $$F_{component} = F \cos(\theta)$$ where $\theta$ is the angle between the force and the axis. 3. **Calculate component along axis $a$:** $$F_a = 1500 \cos 70^\circ$$ $$F_a = 1500 \times 0.3420 = 513 \text{ lb}$$ 4. **Calculate component along axis $b$:** The angle between $F$ and $b$ is $180^\circ - (70^\circ + 35^\circ) = 75^\circ$ because the axes are oblique and the angles sum to $180^\circ$. $$F_b = 1500 \cos 75^\circ$$ $$F_b = 1500 \times 0.2588 = 388 \text{ lb}$$ 5. **Answer:** - Component along $a$: $513$ lb - Component along $b$: $388$ lb