1. **State the problem:** We need to find the force required to keep a 2755 lb car from rolling down a driveway inclined at 25 degrees to the horizontal. 2. **Identify the forces:** The weight of the car acts vertically downward. The component of this weight parallel to the incline causes the car to roll down. 3. **Formula used:** The force required to keep the car from rolling down equals the component of the weight parallel to the incline. This force is given by: $$F = W \sin(\theta)$$ where $W$ is the weight of the car and $\theta$ is the angle of the incline. 4. **Calculate the force:** $$F = 2755 \times \sin(25^\circ)$$ 5. **Evaluate $\sin(25^\circ)$:** $$\sin(25^\circ) \approx 0.4226$$ 6. **Multiply:** $$F = 2755 \times 0.4226 = 1164.6$$ 7. **Interpretation:** The force required to keep the car from rolling down the incline is approximately 1165 lb. **Final answer:** $$\boxed{1165 \text{ lb}}$$