Subjects physics

Friction Deceleration 9809B8

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1. The problem is to find the deceleration when the coefficient of friction $f$ is 0.92. 2. The formula to calculate deceleration due to friction is $$a = f \times g$$ where $a$ is the deceleration, $f$ is the coefficient of friction, and $g$ is the acceleration due to gravity (approximately 9.8 m/s$^2$). 3. Since the coefficient of friction $f = 0.92$, substitute the values into the formula: $$a = 0.92 \times 9.8$$ 4. Calculate the product: $$a = 9.016$$ 5. Therefore, the deceleration is approximately $9.02$ m/s$^2$.