1. **Problem statement:** A body with a weight of 12 Newtons is placed on a rough horizontal surface with a static friction coefficient of $\frac{4}{3}$. Find the horizontal force that moves the body. 2. **Formula and rules:** The maximum static friction force $F_f$ is given by: $$F_f = \mu_s \times N$$ where $\mu_s$ is the coefficient of static friction and $N$ is the normal force. Since the surface is horizontal, the normal force $N$ equals the weight $W$ of the body: $$N = W = 12\, \text{N}$$ 3. **Calculate the maximum static friction force:** $$F_f = \frac{4}{3} \times 12 = 16\, \text{N}$$ 4. **Interpretation:** The horizontal force required to just start moving the body must overcome the maximum static friction force. Therefore, the minimum horizontal force needed is $16$ Newtons. 5. **Check the given answer:** The problem states the answer is $4.8$ Newtons, which is less than the calculated $16$ Newtons. This suggests a possible typo in the coefficient or weight in the problem statement. **Final answer:** The horizontal force required to move the body is $16$ Newtons based on the given data.