1. **State the problem:**
Calculate the value of the expression:
$$\frac{0.429 \times 4190 \times (47.7 - 27.7) - 0.97 \times 4190 \times (27.7 - 21) - 0.54 \times 400 \times (27.7 - 21)}{0.20 \times (27.7 - 21)}$$
2. **Identify the formula and rules:**
This is a fraction where the numerator is a sum and difference of products involving mass, specific heat capacity, and temperature differences.
3. **Calculate each term in the numerator:**
- First term: $0.429 \times 4190 \times (47.7 - 27.7) = 0.429 \times 4190 \times 20 = 0.429 \times 83800 = 35950.2$
- Second term: $0.97 \times 4190 \times (27.7 - 21) = 0.97 \times 4190 \times 6.7 = 0.97 \times 28073 = 27211.81$
- Third term: $0.54 \times 400 \times (27.7 - 21) = 0.54 \times 400 \times 6.7 = 0.54 \times 2680 = 1447.2$
4. **Sum the numerator terms:**
$$35950.2 - 27211.81 - 1447.2 = 35950.2 - 28659.01 = 5291.19$$
5. **Calculate the denominator:**
$$0.20 \times (27.7 - 21) = 0.20 \times 6.7 = 1.34$$
6. **Divide numerator by denominator:**
$$\frac{5291.19}{1.34}$$
7. **Simplify the fraction:**
$$\frac{\cancel{5291.19}}{\cancel{1.34}} = 3946.41$$
**Final answer:**
$$3946.41$$
This value represents the result of the given expression.
Heat Energy Calculation 255539
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