1. **State the problem:** We need to find the displacement and the distance traveled by the iguana between 3 seconds and 6 seconds based on its position-time graph. 2. **Recall definitions:** - Displacement is the change in position, calculated as final position minus initial position. - Distance traveled is the total length of the path covered, regardless of direction. 3. **Identify positions from the graph:** - At $t=3$ seconds, position $x=6$ meters. - At $t=5$ seconds, position remains $6$ meters (no movement). - At $t=6$ seconds, position $x=0$ meters. 4. **Calculate displacement:** $$\text{Displacement} = x_{6s} - x_{3s} = 0 - 6 = -6 \text{ meters}$$ This means the iguana moved 6 meters backward from 3 s to 6 s. 5. **Calculate distance traveled:** - From 3 s to 5 s, the iguana stays at 6 meters, so distance is 0. - From 5 s to 6 s, it moves from 6 meters to 0 meters, so distance is $|0 - 6| = 6$ meters. Total distance traveled between 3 s and 6 s is: $$0 + 6 = 6 \text{ meters}$$ **Final answers:** - Displacement: $-6$ meters - Distance traveled: $6$ meters