Subjects physics

Kinematics Basics 1C1243

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1. The problem statement is unclear as no specific question is asked, but the data provided suggests a kinematics or SUVAT problem involving distances, speeds, accelerations, and times. 2. To solve typical SUVAT problems, we use the equations of motion: $$v = u + at$$ $$s = ut + \frac{1}{2}at^2$$ $$v^2 = u^2 + 2as$$ $$s = \frac{(u+v)}{2}t$$ where $u$ is initial velocity, $v$ is final velocity, $a$ is acceleration, $t$ is time, and $s$ is displacement. 3. Important rules: - Convert all units to SI units (meters, seconds). - Ensure consistent units before calculations. - Use the correct formula based on known and unknown variables. 4. Since no explicit question is given, let's convert the speeds from km/h to m/s for clarity: $$144\ \text{km/h} = \frac{144 \times 1000}{3600} = 40\ \text{m/s}$$ $$60\ \text{km/h} = \frac{60 \times 1000}{3600} = 16.67\ \text{m/s}$$ 5. Example: Calculate the displacement $s$ when initial velocity $u=0$, acceleration $a=4\ \text{m/s}^2$, and time $t=5\ \text{s}$: $$s = ut + \frac{1}{2}at^2 = 0 + \frac{1}{2} \times 4 \times 5^2 = 2 \times 25 = 50\ \text{m}$$ 6. Example: Calculate final velocity $v$ when $u=24\ \text{m/s}$, $a=10\ \text{m/s}^2$, and $t=3\ \text{s}$: $$v = u + at = 24 + 10 \times 3 = 24 + 30 = 54\ \text{m/s}$$ 7. Without a specific question, these are the steps and formulas to approach problems involving the given data. Final answer: Conversion and example calculations provided for clarity.