1. **State the problem:** We have 736 grams of neptunium with a half-life of 2 days. We want to find how much remains after 6 days. 2. **Formula used:** The amount remaining after time $t$ is given by the exponential decay formula: $$ A = A_0 \times \left(\frac{1}{2}\right)^{\frac{t}{T}} $$ where $A_0$ is the initial amount, $T$ is the half-life, and $t$ is the elapsed time. 3. **Substitute values:** $$ A = 736 \times \left(\frac{1}{2}\right)^{\frac{6}{2}} $$ 4. **Simplify the exponent:** $$ \frac{6}{2} = 3 $$ so $$ A = 736 \times \left(\frac{1}{2}\right)^3 $$ 5. **Calculate the power:** $$ \left(\frac{1}{2}\right)^3 = \frac{1}{2^3} = \frac{1}{8} $$ 6. **Multiply:** $$ A = 736 \times \frac{1}{8} $$ 7. **Show cancellation:** $$ A = \cancel{736} \times \frac{1}{\cancel{8}} $$ 8. **Final calculation:** $$ A = 92 $$ **Answer:** After 6 days, 92 grams of neptunium will be left.