1. The problem asks to relate Ohm's Law to electric power consumption. Ohm's Law states that $V = IR$, where $V$ is voltage, $I$ is current, and $R$ is resistance. Electric power consumption is given by $P = VI$. Using Ohm's Law, we can substitute $V = IR$ into the power formula to get $P = I \times IR = I^2 R$ or $P = \frac{V^2}{R}$. This shows that power consumption depends on the current squared times resistance or voltage squared divided by resistance. 2. The problem asks how to compute electric consumption cost if 472 kW is used for 1 month and the charge is 8.75 per kilowatt-hour. Electric consumption cost = Power used (kWh) $\times$ Rate per kWh. Given power used = 472 kW for 1 hour, but since it's for 1 month, we assume 472 kWh total. Cost = $472 \times 8.75 = 4130$. 3. The problem asks what electromotive force (emf) is. Electromotive force (emf) is the energy provided per unit charge by a source like a battery or generator to move charges through a circuit. It is measured in volts and represents the potential difference when no current flows. 4. The problem asks to explain the term emf. EMF is the voltage generated by a source when no current is flowing. It is the maximum potential difference the source can provide. 5. The problem asks to name a source of potential difference. A common source of potential difference is a battery. Summary: Ohm's Law relates voltage, current, and resistance. Power consumption depends on voltage and current. Electric consumption cost is calculated by multiplying power used by rate. EMF is the energy per charge provided by a source. A battery is a source of potential difference.