1. **Problem statement:** A small ball of mass 0.20 kg is attached to a string of length 0.80 m fixed at point S. The ball is released from rest when the string is horizontal. We analyze the situation when the string is vertical.
2. **Relevant formulas and principles:**
- Conservation of mechanical energy: Total mechanical energy at the start equals total mechanical energy at the vertical position.
- Gravitational potential energy (GPE) change converts into kinetic energy (KE).
- Tension in the string provides centripetal force and balances weight component.
3. **Step (a)(i): Show speed of the ball is about 4 m/s when string is vertical.**
- Initial height of the ball relative to vertical position is the length of the string: $h=0.80$ m.
- Initial kinetic energy $KE_i=0$ (released from rest).
- Initial potential energy $PE_i = mg h$.
- At vertical position, height is zero, so $PE_f=0$.
- By conservation of energy:
$$PE_i + KE_i = PE_f + KE_f$$
$$mg h = \frac{1}{2} m v^2$$
- Cancel mass $m$:
$$g h = \frac{1}{2} v^2$$
- Solve for $v$:
$$v = \sqrt{2 g h}$$
- Substitute $g=9.8$ m/s$^2$, $h=0.80$ m:
$$v = \sqrt{2 \times 9.8 \times 0.80} = \sqrt{15.68} \approx 3.96 \text{ m/s}$$
- Rounded to 2 significant figures, $v \approx 4.0$ m/s.
4. **Step (a)(ii): Calculate the tension in the string when vertical.**
- Forces on the ball at vertical position:
- Weight $W = mg = 0.20 \times 9.8 = 1.96$ N downward.
- Tension $T$ upward along the string.
- The ball moves in a circle of radius $r=0.80$ m with speed $v$.
- Centripetal force required:
$$F_c = \frac{m v^2}{r}$$
- Substitute values:
$$F_c = \frac{0.20 \times (3.96)^2}{0.80} = \frac{0.20 \times 15.68}{0.80} = \frac{3.136}{0.80} = 3.92 \text{ N}$$
- Tension must provide centripetal force and balance weight:
$$T - mg = F_c$$
$$T = mg + F_c = 1.96 + 3.92 = 5.88 \text{ N}$$
- Rounded to 2 significant figures, $T \approx 5.9$ N.
**Final answers:**
- Speed of the ball at vertical position: $\boxed{4.0 \text{ m/s}}$
- Tension in the string at vertical position: $\boxed{5.9 \text{ N}}$
Pendulum Tension Speed 57Db0B
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