1. The problem is to calculate the power $P_2$ dissipated by a resistor $R_2$ given the output voltage $V_{out}$ and the resistance $R_2$. 2. The formula for power dissipated by a resistor is: $$P = \frac{V^2}{R}$$ where $V$ is the voltage across the resistor and $R$ is the resistance. 3. Given: $$V_{out} = 4.91$$ $$R_2 = 51$$ 4. Substitute the values into the formula: $$P_2 = \frac{4.91^2}{51}$$ 5. Calculate the numerator: $$4.91^2 = 24.1081$$ 6. Now divide by the resistance: $$P_2 = \frac{24.1081}{51}$$ 7. Simplify the fraction: $$P_2 = \cancel{\frac{24.1081}{51}} = 0.4725$$ 8. Round to two decimal places: $$P_2 \approx 0.47$$ 9. Therefore, the power dissipated by resistor $R_2$ is approximately 0.47 watts.