1. **State the problem:**
A 60.0-kg boy runs up a flight of stairs 10.0 m high in 8.00 s. We need to find the minimum rate at which he uses energy, which is the power output.
2. **Formula used:**
Power $P$ is the rate of doing work or using energy, given by
$$P = \frac{W}{t}$$
where $W$ is work done and $t$ is time.
3. **Work done:**
The work done to raise the boy to height $h$ against gravity is the change in gravitational potential energy:
$$W = mgh$$
where $m = 60.0$ kg, $g = 9.8$ m/s$^2$, and $h = 10.0$ m.
4. **Calculate work done:**
$$W = 60.0 \times 9.8 \times 10.0 = 5880 \text{ J}$$
5. **Calculate power:**
$$P = \frac{5880}{8.00} = 735 \text{ W}$$
6. **Interpretation:**
The minimum rate of energy use (power) is 735 W.
**Final answer:** B) 735 W
Power Stairs Af60Ba
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