1. **State the problem:** We have data of potential difference (voltage) $V$ and current $I$ for a resistor. We need to plot the data and calculate the resistance $R$. 2. **Formula used:** Ohm's Law states that $V = IR$, where $R$ is resistance. 3. **Important rule:** Resistance $R$ is constant for a resistor, so the ratio $\frac{V}{I}$ should be constant. 4. **Calculate resistance for each data point:** $$R = \frac{V}{I}$$ - For $V=2.5$, $I=0.002$: $$R = \frac{2.5}{0.002} = 1250$$ - For $V=6.0$, $I=0.005$: $$R = \frac{6.0}{0.005} = 1200$$ - For $V=8.7$, $I=0.007$: $$R = \frac{8.7}{0.007} \approx 1242.86$$ - For $V=11.6$, $I=0.009$: $$R = \frac{11.6}{0.009} \approx 1288.89$$ - For $V=14.5$, $I=0.012$: $$R = \frac{14.5}{0.012} \approx 1208.33$$ 5. **Average resistance:** $$R_{avg} = \frac{1250 + 1200 + 1242.86 + 1288.89 + 1208.33}{5} = \frac{6189.08}{5} = 1237.82$$ 6. **Interpretation:** The resistance is approximately $1238$ ohms. 7. **Plot:** The points $(2.5,0.002)$, $(6.0,0.005)$, $(8.7,0.007)$, $(11.6,0.009)$, and $(14.5,0.012)$ lie roughly on a straight line through the origin, confirming Ohm's law. **Final answer:** The resistance of the resistor is approximately $1238$ ohms.