1. **Problem 1: Fill in the table for the circuit with resistors R1=220 Ω, R2=130 Ω, R3=470 Ω, R4=100 Ω, R5=270 Ω.** 2. The table requires values for Voltage (V), Current (I), Resistance (R), and Power (P) for each resistor and total. 3. **Step 1: Understand the circuit configuration.** - Since the circuit diagram is not provided, assume resistors are connected in series or parallel as per typical problems. - For this problem, let's assume all resistors are in series (common in such tables). 4. **Step 2: Calculate total resistance.** - For series, total resistance $$R_{total} = R_1 + R_2 + R_3 + R_4 + R_5 = 220 + 130 + 470 + 100 + 270 = 1190\ \Omega$$ 5. **Step 3: Calculate total current if total voltage is known.** - Voltage is not given, so we cannot calculate current or power without voltage. 6. **Step 4: Calculate voltage across each resistor.** - Voltage across resistor $$R_i$$ in series is $$V_i = I \times R_i$$. - Without total voltage or current, these cannot be calculated. 7. **Step 5: Calculate power for each resistor.** - Power $$P_i = I^2 \times R_i = \frac{V_i^2}{R_i}$$. - Again, without voltage or current, power cannot be calculated. **Conclusion:** - Without total voltage or current, only resistance values can be filled. --- **Problem 2: Fill in the table for the circuit with resistors R1=220 Ω, R2=130 Ω, R3=470 Ω, and total voltage 12 volts.** 1. **Step 1: Identify circuit configuration.** - Assume series connection for simplicity. 2. **Step 2: Calculate total resistance:** $$R_{total} = 220 + 130 + 470 = 820\ \Omega$$ 3. **Step 3: Calculate total current using Ohm's law:** $$I = \frac{V_{total}}{R_{total}} = \frac{12}{820} \approx 0.01463\ A$$ 4. **Step 4: Calculate voltage across each resistor:** $$V_1 = I \times R_1 = 0.01463 \times 220 \approx 3.22\ V$$ $$V_2 = I \times R_2 = 0.01463 \times 130 \approx 1.90\ V$$ $$V_3 = I \times R_3 = 0.01463 \times 470 \approx 6.88\ V$$ 5. **Step 5: Calculate power dissipated by each resistor:** $$P_1 = I^2 \times R_1 = (0.01463)^2 \times 220 \approx 0.047\ W$$ $$P_2 = (0.01463)^2 \times 130 \approx 0.028\ W$$ $$P_3 = (0.01463)^2 \times 470 \approx 0.101\ W$$ 6. **Step 6: Fill in the table:** | Resistor | V (Volts) | I (Amps) | R (Ohms) | P (Watts) | |---------|-----------|----------|----------|-----------| | R1 | 3.22 | 0.01463 | 220 | 0.047 | | R2 | 1.90 | 0.01463 | 130 | 0.028 | | R3 | 6.88 | 0.01463 | 470 | 0.101 | | Total | 12 | 0.01463 | 820 | 0.176 | **Final answer:** - Total current $$I = 0.01463\ A$$ - Voltage and power as above.