1. **Problem Statement:** A body moves 6 m north, 8 m east, and 10 m vertically upwards. We need to find its resultant displacement from the initial position. 2. **Formula Used:** The resultant displacement in 3D space can be found using the Pythagorean theorem extended to three dimensions: $$ R = \sqrt{x^2 + y^2 + z^2} $$ where $x$, $y$, and $z$ are the displacements along the east, north, and vertical directions respectively. 3. **Given Values:** - $x = 8$ m (east) - $y = 6$ m (north) - $z = 10$ m (upwards) 4. **Calculation:** $$ R = \sqrt{8^2 + 6^2 + 10^2} = \sqrt{64 + 36 + 100} = \sqrt{200} $$ 5. **Simplification:** $$ \sqrt{200} = \sqrt{100 \times 2} = 10\sqrt{2} \approx 14.14 \text{ m} $$ 6. **Conclusion:** The resultant displacement from the initial position is approximately 14.14 meters.