1. **State the problem:** We have a screw jack with a pitch of 0.5 cm and a handle length of 2 cm. We want to determine the mechanical advantage or related parameters. 2. **Relevant formula:** The ideal mechanical advantage (IMA) of a screw jack is given by: $$\text{IMA} = \frac{2\pi r}{p}$$ where $r$ is the radius of the handle and $p$ is the pitch of the screw. 3. **Given values:** - Pitch, $p = 0.5$ cm - Handle length (radius), $r = 2$ cm 4. **Calculate IMA:** $$\text{IMA} = \frac{2\pi \times 2}{0.5} = \frac{4\pi}{0.5} = 8\pi$$ 5. **Simplify:** $$8\pi \approx 8 \times 3.1416 = 25.13$$ 6. **Interpretation:** The ideal mechanical advantage of the screw jack is approximately 25.13, meaning the force applied at the handle is amplified about 25 times at the screw.