1. **State the problem:** We need to find the specific gravity of jet fuel, which is the ratio of the density of the jet fuel to the density of water.
2. **Recall the formulas:**
- Density is mass divided by volume: $$\text{Density} = \frac{\text{Mass}}{\text{Volume}}$$
- Specific gravity is the ratio of the density of the substance to the density of water: $$\text{Specific Gravity} = \frac{\text{Density of substance}}{\text{Density of water}}$$
3. **Calculate the density of jet fuel:**
- Mass of jet fuel = 2325 kg
- Volume of jet fuel = 760 gallons
$$\text{Density of jet fuel} = \frac{2325}{760} \approx 3.0592\ \text{kg/gallon}$$
4. **Calculate the density of water:**
- Given mass of 1 gallon of water = 3.8 kg
- Volume of water = 1 gallon
$$\text{Density of water} = \frac{3.8}{1} = 3.8\ \text{kg/gallon}$$
5. **Calculate the specific gravity:**
$$\text{Specific Gravity} = \frac{3.0592}{3.8}$$
6. **Show intermediate cancellation:**
$$\text{Specific Gravity} = \frac{\cancel{3.0592}}{\cancel{3.8}} \approx 0.8051$$
7. **Round to the nearest tenth:**
$$0.8051 \approx 0.8$$
**Final answer:** The specific gravity of jet fuel is approximately **0.8**.
Specific Gravity 0944Cd
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.