1. **State the problem:** A student is at the edge of a canyon 260 m wide and hears her echo 1.5 s later. We need to find the speed of sound waves.
2. **Understand the echo:** The sound travels to the opposite side of the canyon and back, so the total distance traveled by the sound is twice the width of the canyon.
3. **Write the formula for speed:** Speed is distance divided by time, so
$$\text{speed} = \frac{\text{distance}}{\text{time}}$$
4. **Calculate the total distance:**
$$\text{distance} = 2 \times 260 = 520 \text{ meters}$$
5. **Calculate the speed:**
$$\text{speed} = \frac{520}{1.5}$$
6. **Simplify the fraction:**
$$\text{speed} = \frac{\cancel{520}}{\cancel{1.5}} = 346.67 \text{ m/s (approx)}$$
7. **Final answer:** The speed of sound waves is approximately **347 m/s**, which is close to the given value of $3.5 \times 10^{2}$ m/s.
Speed Echo 87656B
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