1. **State the problem:** We need to find the force required to start moving a 35 kg crate given the coefficient of static friction $\mu_s = 0.35$. 2. **Formula used:** The force to overcome static friction is given by $$F_{static} = \mu_s \times F_N$$ where $F_N$ is the normal force. 3. **Calculate the normal force:** Since the crate is on a horizontal surface and not accelerating vertically, $$F_N = mg$$ where $m = 35$ kg and $g = 9.8$ m/s$^2$ (acceleration due to gravity). 4. **Calculate $F_N$:** $$F_N = 35 \times 9.8 = 343 \text{ N}$$ 5. **Calculate the force to start moving the crate:** $$F_{static} = 0.35 \times 343 = 120.05 \text{ N}$$ 6. **Interpretation:** You need to push with a force slightly greater than $120.05$ N to overcome static friction and start moving the crate. **Final answer:** $$\boxed{120.05 \text{ N}}$$