1. Let's state the problem: A beam has a 300 N force acting on its outermost side and an additional 300 N load hanging from it. We want to find the total torque. 2. The formula for torque ($\tau$) is: $$\tau = F \times r$$ where $F$ is the force and $r$ is the distance from the pivot point. 3. If the beam length is 4 units and both forces act at the outermost side, the total force is: $$300 + 300 = 600\ \text{N}$$ 4. Therefore, the total torque is: $$\tau = 4 \times 600$$ 5. Calculating the torque: $$\tau = 2400\ \text{N}\cdot\text{units}$$ 6. So yes, the total torque is $2400$ when both forces act at the same distance of 4 units from the pivot. This assumes both forces act at the same point or line of action at the outermost side of the beam.