1. **State the problem:** A train with mass 100t (100,000 kg) accelerates from rest to 720 kph in 50 seconds. We need to find:
- Average acceleration
- Force required to produce this acceleration
- Inertia force on the train
2. **Convert units:**
- Velocity from 720 kph to m/s:
$$720 \text{ kph} = 720 \times \frac{1000}{3600} = 200 \text{ m/s}$$
3. **Calculate average acceleration:**
Using the formula for acceleration:
$$a = \frac{\Delta v}{\Delta t}$$
where $\Delta v = 200 - 0 = 200$ m/s and $\Delta t = 50$ s.
$$a = \frac{200}{50} = 4 \text{ m/s}^2$$
4. **Calculate force required:**
Using Newton's second law:
$$F = m \times a$$
where $m = 100,000$ kg and $a = 4$ m/s$^2$.
$$F = 100,000 \times 4 = 400,000 \text{ N}$$
5. **Inertia force:**
The inertia force is the force needed to overcome the train's resistance to acceleration, which is the same as the force calculated above:
$$F_{inertia} = 400,000 \text{ N}$$
**Final answers:**
- Average acceleration: $4$ m/s$^2$
- Force required: $400,000$ N
- Inertia force: $400,000$ N
Train Acceleration 326093
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