1. **Stating the problem:** A driver travels from Bolga to Walawale, a distance of 40 miles. The driver stops at Kalminga, 10 miles from Bolga, after 60 minutes. After a 30-minute stop, the driver continues to Walawale in 60 minutes. Then, after 30 minutes, the driver returns to Bolga in 120 minutes. 2. **Goal:** Calculate the average speed for each segment of the journey. 3. **Formula used:** Speed is calculated by the formula $$\text{Speed} = \frac{\text{Distance}}{\text{Time}}$$ where distance is in miles and time is in hours. 4. **Segment 1: Bolga to Kalminga** - Distance = 10 miles - Time = 60 minutes = $\frac{60}{60} = 1$ hour - Speed = $$\frac{10}{1} = 10$$ miles per hour 5. **Segment 2: Kalminga to Walawale** - Distance = 40 - 10 = 30 miles - Time = 60 minutes = $\frac{60}{60} = 1$ hour - Speed = $$\frac{30}{1} = 30$$ miles per hour 6. **Segment 3: Walawale to Bolga (return journey)** - Distance = 40 miles - Time = 120 minutes = $\frac{120}{60} = 2$ hours - Speed = $$\frac{40}{2} = 20$$ miles per hour 7. **Summary:** - Speed from Bolga to Kalminga: 10 mph - Speed from Kalminga to Walawale: 30 mph - Speed from Walawale back to Bolga: 20 mph This shows the driver traveled slower on the first segment, faster on the second, and at a moderate speed on the return trip.