1. **State the problem:** An object is suspended from a scale inside an elevator accelerating upwards at $1.25\ \text{m/s}^2$. The scale reads a mass of 45 kg. We need to find the true mass of the object.
2. **Relevant formula:** The scale measures the apparent weight, which changes due to acceleration. The apparent weight $W_{apparent}$ relates to true mass $m$ and acceleration $a$ by:
$$W_{apparent} = m(g + a)$$
where $g = 9.8\ \text{m/s}^2$ is gravitational acceleration.
3. **Convert scale reading to force:** The scale reading in kg can be converted to force (weight) by multiplying by $g$:
$$F_{apparent} = 45 \times 9.8 = 441\ \text{N}$$
4. **Use the formula to find true mass:** Rearranging the formula:
$$m = \frac{F_{apparent}}{g + a}$$
Substitute values:
$$m = \frac{441}{9.8 + 1.25} = \frac{441}{11.05} \approx 39.91\ \text{kg}$$
5. **Interpretation:** The true mass of the object is approximately 39.91 kg, less than the apparent mass due to the elevator's upward acceleration.
**Final answer:** The true mass of the object is approximately **39.91 kg**.
True Mass Elevator 5F3Cf2
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