1. **State the problem:** An object has a volume of 3000 cm³ and an apparent weight of 43 N when immersed in a liquid with density 900 kg/m³. Calculate the true weight of the object. Given acceleration due to gravity $g=10$ m/s². 2. **Relevant formulas:** - Apparent weight $W_a = W - F_b$ where $W$ is true weight and $F_b$ is buoyant force. - Buoyant force $F_b = \rho V g$ where $\rho$ is liquid density, $V$ is volume, and $g$ is gravity. 3. **Convert volume to cubic meters:** $$V = 3000 \text{ cm}^3 = 3000 \times 10^{-6} = 0.003 \text{ m}^3$$ 4. **Calculate buoyant force:** $$F_b = \rho V g = 900 \times 0.003 \times 10 = 27 \text{ N}$$ 5. **Calculate true weight:** $$W = W_a + F_b = 43 + 27 = 70 \text{ N}$$ **Final answer:** The true weight of the object is $70$ N.