1. **State the problem:** Given an object with initial velocity $o=50$ and angle $28^\circ$, find the components of the velocity. 2. **Formula used:** To find the horizontal and vertical components of velocity, use: $$v_x = o \cos(\theta)$$ $$v_y = o \sin(\theta)$$ where $o$ is the initial velocity and $\theta$ is the angle. 3. **Calculate horizontal component:** $$v_x = 50 \cos(28^\circ)$$ Using $\cos(28^\circ) \approx 0.8829$, $$v_x = 50 \times 0.8829 = 44.145$$ 4. **Calculate vertical component:** $$v_y = 50 \sin(28^\circ)$$ Using $\sin(28^\circ) \approx 0.4695$, $$v_y = 50 \times 0.4695 = 23.475$$ 5. **Final answer:** The velocity components are: - Horizontal velocity $v_x \approx 44.15$ - Vertical velocity $v_y \approx 23.48$