1. **State the problem:** A hand glider dives at 25 mph at an angle of 60° below the horizontal (East). We need to find the component form of the velocity vector. 2. **Formula and explanation:** The velocity vector components can be found using trigonometry: $$v_x = v \cos(\theta)$$ $$v_y = v \sin(\theta)$$ where $v = 25$ mph and $\theta = 60^\circ$ below the horizontal means the vertical component is negative. 3. **Calculate the horizontal component:** $$v_x = 25 \cos(60^\circ) = 25 \times \frac{1}{2} = \frac{25}{2}$$ 4. **Calculate the vertical component:** $$v_y = 25 \sin(-60^\circ) = 25 \times -\frac{\sqrt{3}}{2} = -\frac{25\sqrt{3}}{2}$$ 5. **Write the velocity vector:** $$\left( \frac{25}{2}, -\frac{25\sqrt{3}}{2} \right)$$ 6. **Interpretation:** The horizontal component is positive (to the right), and the vertical component is negative (downward), matching the direction 60° below horizontal. **Final answer:** The component form of the velocity vector is $\boxed{\left( \frac{25}{2}, -\frac{25\sqrt{3}}{2} \right)}$.