1. **State the problem:** We need to find the mass of water inside a spherical balloon filled with water. 2. **Given data:** - Density of water $\rho = 1$ g/cm$^3$ - Radius of the sphere $r = 5$ cm 3. **Formula used:** The mass $m$ of an object is given by the formula: $$m = \rho \times V$$ where $V$ is the volume of the object. 4. **Volume of a sphere:** The volume $V$ of a sphere with radius $r$ is: $$V = \frac{4}{3} \pi r^3$$ 5. **Calculate the volume:** $$V = \frac{4}{3} \pi (5)^3 = \frac{4}{3} \pi 125 = \frac{500}{3} \pi$$ 6. **Calculate the mass:** $$m = 1 \times \frac{500}{3} \pi = \frac{500}{3} \pi$$ 7. **Approximate the mass:** Using $\pi \approx 3.1416$, $$m \approx \frac{500}{3} \times 3.1416 = 523.6$$ **Final answer:** The mass of the water inside the balloon is approximately **523.6 grams**.