1. **State the problem:** We need to find the probability that a card drawn from a standard deck of 52 cards is either a black card or a 10. 2. **Recall the formula for probability:** $$\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$$ 3. **Identify the total number of outcomes:** There are 52 cards in total. 4. **Count the favorable outcomes:** - Number of black cards: There are 2 suits that are black (clubs and spades), each with 13 cards, so $2 \times 13 = 26$ black cards. - Number of 10s: There are 4 tens (one in each suit). 5. **Avoid double counting:** Among the 10s, two are black (10 of clubs and 10 of spades), which are already counted in the black cards. 6. **Calculate the total favorable outcomes:** $$26 + 4 - 2 = 28$$ 7. **Calculate the probability:** $$\frac{28}{52}$$ 8. **Simplify the fraction:** $$\frac{\cancel{28}^{14}}{\cancel{52}^{26}} = \frac{14}{26}$$ $$\frac{\cancel{14}^7}{\cancel{26}^{13}} = \frac{7}{13}$$ 9. **Final answer:** The probability that the card is a black card or a 10 is $\frac{7}{13}$.