1. **Problem statement:** Find the probability that a randomly selected patio table is Blue or Small. 2. **Given data:** - Total tables: 58 - Blue tables: 19 - Small tables: 19 - Small and Blue tables: 2 3. **Formula used:** The probability of A or B is given by the formula: $$P(A \cup B) = P(A) + P(B) - P(A \cap B)$$ where: - $P(A)$ is the probability of event A (Blue tables), - $P(B)$ is the probability of event B (Small tables), - $P(A \cap B)$ is the probability of both A and B (Small and Blue tables). 4. **Calculate each probability:** $$P(Blue) = \frac{19}{58}$$ $$P(Small) = \frac{19}{58}$$ $$P(Small \cap Blue) = \frac{2}{58}$$ 5. **Apply the formula:** $$P(Blue \cup Small) = \frac{19}{58} + \frac{19}{58} - \frac{2}{58} = \frac{19 + 19 - 2}{58} = \frac{36}{58}$$ 6. **Simplify the fraction:** $$\frac{36}{58} = \frac{\cancel{2} \times 18}{\cancel{2} \times 29} = \frac{18}{29}$$ 7. **Convert to decimal:** $$\frac{18}{29} \approx 0.6207$$ **Final answer:** The probability that the patio table is Blue or Small is approximately **0.6207**.