1. **State the problem:** We need to find from which bag Greg is less likely to pick a blue tile. 2. **Formula for probability:** Probability of an event = \( \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \). 3. **Calculate probability for the first bag:** \[ P_1 = \frac{10}{25} \] 4. **Calculate probability for the second bag:** \[ P_2 = \frac{75}{250} \] 5. **Simplify both fractions:** \[ P_1 = \frac{10}{25} = \frac{\cancel{5} \times 2}{\cancel{5} \times 5} = \frac{2}{5} = 0.4 \] \[ P_2 = \frac{75}{250} = \frac{\cancel{25} \times 3}{\cancel{25} \times 10} = \frac{3}{10} = 0.3 \] 6. **Compare probabilities:** \[ 0.4 > 0.3 \] 7. **Conclusion:** Greg is less likely to pick a blue tile from the second bag because its probability is lower. **Final answer:** Greg is less likely to pick a blue tile from the second bag. The probability of picking a blue tile from the first bag is 0.4, while the probability of picking a blue tile from the second bag is 0.3.