1. **Problem Statement:** Find the probability that the first card drawn is red and the second card drawn is black from a standard 52-card deck.
2. **Key Information:**
- Total cards: 52
- Red cards: 26 (hearts and diamonds)
- Black cards: 26 (clubs and spades)
3. **Part (A) Without Replacement:**
- The first card is red: Probability = $\frac{26}{52} = \frac{1}{2}$
- After drawing one red card, cards left = 51
- Black cards remain 26 (unchanged)
- Probability second card is black = $\frac{26}{51}$
4. **Combined Probability (without replacement):**
$$
P = \frac{26}{52} \times \frac{26}{51} = \frac{1}{2} \times \frac{26}{51} = \frac{26}{102} = \frac{13}{51} \approx 0.2549
$$
5. **Part (B) With Replacement:**
- The first card is red: Probability = $\frac{26}{52} = \frac{1}{2}$
- Since the card is replaced, the deck is back to 52 cards
- Probability second card is black = $\frac{26}{52} = \frac{1}{2}$
6. **Combined Probability (with replacement):**
$$
P = \frac{26}{52} \times \frac{26}{52} = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} = 0.25
$$
**Final answers:**
- (A) Without replacement: $0.2549$
- (B) With replacement: $0.25$
Card Probability 18F862
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.