1. **State the problem:** We want to find the probability $P(E')$ of drawing any card except the 3 of diamonds from a standard 52-card deck. 2. **Formula for probability of the complement event:** $$P(E') = 1 - P(E)$$ where $P(E)$ is the probability of drawing the 3 of diamonds. 3. **Calculate $P(E)$:** There is exactly one 3 of diamonds in the deck, so $$P(E) = \frac{1}{52}$$ 4. **Calculate $P(E')$:** $$P(E') = 1 - \frac{1}{52} = \frac{52}{52} - \frac{1}{52} = \frac{51}{52}$$ 5. **Interpretation:** The probability of drawing any card except the 3 of diamonds is $\frac{51}{52}$, which is already in simplest form.