1. **State the problem:** We want to find the probability of winning a carnival game where winning means tossing a coin and getting Heads, and rolling a die and getting a 6. 2. **Formula and rules:** The probability of two independent events both happening is the product of their individual probabilities. 3. **Calculate individual probabilities:** - Probability of getting Heads on a coin toss is $\frac{1}{2}$. - Probability of rolling a 6 on a die is $\frac{1}{6}$. 4. **Calculate combined probability:** $$ P(\text{Heads and 6}) = P(\text{Heads}) \times P(6) = \frac{1}{2} \times \frac{1}{6} = \frac{1}{12} $$ 5. **Final answer:** The probability of winning the game is $\frac{1}{12}$.