1. The problem is to find the probability of getting exactly 2 tails when a fair coin is tossed three times. 2. The total number of possible outcomes when tossing a coin three times is $2^3 = 8$. 3. The number of ways to get exactly 2 tails is the number of combinations of 3 tosses taken 2 at a time: $$\binom{3}{2} = 3$$. 4. Therefore, the probability is $$\frac{3}{8}$$. 5. The correct answer is C.