1. The problem asks for the probability of tossing two heads and one tail in three coin tosses. 2. The formula for probability is $P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. 3. Each coin toss has 2 possible outcomes: Head (H) or Tail (T). 4. For three tosses, total outcomes are $2^3 = 8$. 5. The favorable outcomes for exactly two heads and one tail are: HHT, HTH, THH. 6. Number of favorable outcomes = 3. 7. Therefore, the probability is $P = \frac{3}{8}$. 8. The radical probability means expressing the probability in simplest radical form if possible, but $\frac{3}{8}$ is already in simplest form. Final answer: $\boxed{\frac{3}{8}}$