1. **State the problem:** We need to find the conditional probability $P(C|D)$, which is the probability of event $C$ occurring given that event $D$ has occurred. 2. **Recall the formula for conditional probability:** $$P(C|D) = \frac{P(C \cap D)}{P(D)}$$ This means we divide the probability of both $C$ and $D$ happening by the probability of $D$ happening. 3. **Identify values from the table:** - $P(C \cap D)$ is the probability of both $C$ and $D$, which from the table is 0.30. - $P(D)$ is the total probability of $D$, which from the table is 0.85. 4. **Calculate $P(C|D)$:** $$P(C|D) = \frac{0.30}{0.85}$$ 5. **Show intermediate step with cancellation:** $$P(C|D) = \frac{\cancel{0.30}}{\cancel{0.85}}$$ (Here, no common factors to cancel, so this is just to show the division step.) 6. **Perform the division:** $$P(C|D) \approx 0.3529$$ 7. **Round to two decimal places:** $$P(C|D) \approx 0.35$$ **Final answer:** $$\boxed{0.35}$$