1. **State the problem:** We have two plants producing parts. Plant 1 produces 1500 parts with 150 defective, and Plant 2 produces 2800 parts with 260 defective. A part is randomly selected and found defective. We want the probability it came from Plant 2.
2. **Identify the formula:** We use Bayes' theorem for conditional probability:
$$P(\text{Plant 2} | \text{Defective}) = \frac{P(\text{Defective} | \text{Plant 2}) \times P(\text{Plant 2})}{P(\text{Defective})}$$
3. **Calculate each probability:**
- Total parts = $1500 + 2800 = 4300$
- $P(\text{Plant 1}) = \frac{1500}{4300}$
- $P(\text{Plant 2}) = \frac{2800}{4300}$
- $P(\text{Defective} | \text{Plant 1}) = \frac{150}{1500} = \frac{1}{10}$
- $P(\text{Defective} | \text{Plant 2}) = \frac{260}{2800} = \frac{13}{140}$
4. **Calculate total defective probability:**
$$P(\text{Defective}) = P(\text{Defective} | \text{Plant 1}) \times P(\text{Plant 1}) + P(\text{Defective} | \text{Plant 2}) \times P(\text{Plant 2})$$
$$= \frac{1}{10} \times \frac{1500}{4300} + \frac{13}{140} \times \frac{2800}{4300}$$
5. **Simplify:**
$$= \frac{1500}{43000} + \frac{13 \times 2800}{140 \times 4300} = \frac{1500}{43000} + \frac{36400}{602000}$$
6. **Convert to common denominator and add:**
$$\frac{1500}{43000} = \frac{1500 \times 14}{43000 \times 14} = \frac{21000}{602000}$$
$$P(\text{Defective}) = \frac{21000}{602000} + \frac{36400}{602000} = \frac{57400}{602000}$$
7. **Calculate numerator for Bayes' theorem:**
$$P(\text{Defective} | \text{Plant 2}) \times P(\text{Plant 2}) = \frac{13}{140} \times \frac{2800}{4300} = \frac{13 \times 2800}{140 \times 4300} = \frac{36400}{602000}$$
8. **Apply Bayes' theorem:**
$$P(\text{Plant 2} | \text{Defective}) = \frac{\frac{36400}{602000}}{\frac{57400}{602000}} = \frac{36400}{\cancel{602000}} \times \frac{\cancel{602000}}{57400} = \frac{36400}{57400}$$
9. **Simplify fraction:**
$$\frac{36400}{57400} = \frac{364}{574} = \frac{182}{287}$$
10. **Final answer:**
$$P(\text{Plant 2} | \text{Defective}) = \frac{182}{287} \approx 0.634$$
So, the probability that a defective part came from Plant 2 is approximately 0.634 or 63.4%.
Defective Part Probability 23Af03
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