1. **Problem statement:** Two unbiased dice are thrown. Find the probability that the total of the numbers on the dice is greater than 10. 2. **Formula and rules:** The probability of an event is given by: $$\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$$ Each die has 6 faces, so the total number of possible outcomes when two dice are thrown is: $$6 \times 6 = 36$$ 3. **Favorable outcomes:** We want the sum of the two dice to be greater than 10. The possible sums greater than 10 are 11 and 12. - Sum = 11: Possible pairs are (5,6) and (6,5) → 2 outcomes - Sum = 12: Possible pair is (6,6) → 1 outcome Total favorable outcomes = 2 + 1 = 3 4. **Calculate probability:** $$\text{Probability} = \frac{3}{36} = \frac{1}{12}$$ **Final answer:** The probability that the total of the numbers on the dice is greater than 10 is $\frac{1}{12}$.