1. The problem states: A fair six-sided die is tossed. The player loses 5 pesos if the result is “1”, loses 5 pesos if the result is “6”, and wins 10 pesos for the other numbers (2, 3, 4, 5). 2. We want to find the table that best describes the problem in terms of outcomes (x) and their probabilities. 3. The outcomes and their probabilities are: - Lose 5 pesos if result is 1 (probability $\frac{1}{6}$) - Lose 5 pesos if result is 6 (probability $\frac{1}{6}$) - Win 10 pesos if result is 2, 3, 4, or 5 (probability $\frac{4}{6}$) 4. The correct table should list the outcomes as the amounts won or lost, and the probabilities as the chance of each outcome. 5. Option a shows: Probability: $-5$, $-5$, $+10$ x: $\frac{1}{6}$, $\frac{1}{6}$, $\frac{4}{6}$ This incorrectly swaps the labels of probability and outcomes. 6. Option b shows: x: $-5$, $-5$, $+10$ Probability: $\frac{1}{6}$, $\frac{1}{6}$, $\frac{4}{6}$ This correctly lists the outcomes and their probabilities. 7. Option c is "None of the choices". 8. Option d shows: x: 1, 1, 6 Probability: $-5$, $-5$, 10 This incorrectly assigns probabilities as amounts and outcomes as numbers. 9. Therefore, the best table that describes the problem is option b. **Final answer:** Option b