1. **Stating the problem:** Two fair six-sided dice are rolled, and the numbers on the two dice are added together to give a score. We need to find the most likely score. 2. **Formula and rules:** The total number of outcomes when rolling two dice is $6 \times 6 = 36$ because each die has 6 faces. 3. **Possible sums and their frequencies:** - Sum 2: (1,1) → 1 way - Sum 3: (1,2), (2,1) → 2 ways - Sum 4: (1,3), (2,2), (3,1) → 3 ways - Sum 5: (1,4), (2,3), (3,2), (4,1) → 4 ways - Sum 6: (1,5), (2,4), (3,3), (4,2), (5,1) → 5 ways - Sum 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) → 6 ways - Sum 8: (2,6), (3,5), (4,4), (5,3), (6,2) → 5 ways - Sum 9: (3,6), (4,5), (5,4), (6,3) → 4 ways - Sum 10: (4,6), (5,5), (6,4) → 3 ways - Sum 11: (5,6), (6,5) → 2 ways - Sum 12: (6,6) → 1 way 4. **Finding the most likely score:** The sum with the highest number of ways is 7 with 6 ways. 5. **Final answer:** The most likely score is **7**.