1. **State the problem:** We roll two fair dice and want to find the probability that the sum of the dots on the two dice is less than or equal to 10. 2. **Formula and rules:** The total number of possible outcomes when rolling two dice is $6 \times 6 = 36$ because each die has 6 faces. 3. **Find favorable outcomes:** We count the number of outcomes where the sum is $\leq 10$. - The sums possible range from 2 to 12. - We exclude sums 11 and 12. 4. **Count sums 11 and 12:** - Sum 11: (5,6), (6,5) → 2 outcomes - Sum 12: (6,6) → 1 outcome 5. **Calculate favorable outcomes:** $$ \text{Favorable outcomes} = 36 - (2 + 1) = 33 $$ 6. **Calculate probability:** $$ P(\text{sum} \leq 10) = \frac{33}{36} = \frac{11}{12} $$ 7. **Final answer:** The probability of getting a sum less than or equal to 10 is $\frac{11}{12}$.